Former champions Bangladesh will start the super six campaign of the ICC U-19 Men's World Cup' 2024 taking on their South Asian rivals Nepal, the 3rd ranked team of Group D on Wednesday, reports UNB.
The match will kick at 2 pm (Bangladesh time) at Mangaung Oval, Bloemfontein in South Africa.
They will play Group D champions Pakistan in the other super six match at Benoni in South Africa on Saturday (February 3).
After the 16- team first group phase ended on Sunday, top 12 teams, divided in two groups, entered the super six stage.
The Super Six will involve the top three sides from each of the four round-robin groups, with teams progressing from Groups A and D comprising one Group while the teams from B and C in another group.
Each of the teams will carry forward their points and net run rate (NRR) in the super six stage which they earned in the group stage matches.
The six teams, which made super six berth from group A and D are: India, Bangladesh, Ireland (Group A) Pakistan, New Zealand and Nepal ( Group D).
South Africa, England, West Indies, Australia, Sri Lanka, and Zimbabwe qualified for the super six stage from Group B and C respectively.
The remaining four teams --USA, Afghanistan, Namibia and Scotland – which didn't make the super six berth-– will compete in the play-off matches for the last four places of the tournament.
The teams will play two matches in the Super Six stage against their opponents from the corresponding group which finished in a different position in their group.
That means India (toppers of Group A) will face off against New Zealand (second position in Group D while Nepal, third position in Group D) will play Bangladesh, the 2nd team of Group A) .
The two semi-final matches scheduled to be held on February 6 and 8 respectively while the final is set to take place on ( February 11), with all three knockout games set to take place in Benoni.
Bd-pratidin English/Tanvir Raihan
